Day of the Week in Python

Given a date, return the corresponding day of the week for that date.

The input is given as three integers representing the day, month and year respectively.

Return the answer as one of the following values {"Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"}.

Example 1:

Input: day = 31, month = 8, year = 2019

Output: "Saturday"

Example 2:

Input: day = 18, month = 7, year = 1999

Output: "Sunday"

Example 3:

Input: day = 15, month = 8, year = 1993

Output: "Sunday"

Constraints:

The given dates are valid dates between the years 1971 and 2100.
class Solution(object):
    def dayOfTheWeek(day, month, year):
        week = ["Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"]
        arr = [ 0, 3, 2, 5, 0, 3, 5, 1, 4, 6, 2, 4 ] 
        year -= month < 3
        
        return week[((year  + int(year / 4) - int(year / 100) + int(year / 400) + arr[month - 1] + day) % 7)]

# answer 1        
day = 31
month = 8
year = 2019
print(Solution.dayOfTheWeek(day, month, year))

# answer 2
day = 18
month = 7
year = 1999
print(Solution.dayOfTheWeek(day, month, year))

# answer 3
day = 15
month = 8
year = 1993
print(Solution.dayOfTheWeek(day, month, year))