**Problem: **

Given an array `nums`

of integers, return how many of them contain an **even number** of digits.

**Example:**

```
Input: nums = [12,345,2,6,7896]
Output: 2
Explanation:
12 contains 2 digits (even number of digits).
345 contains 3 digits (odd number of digits).
2 contains 1 digit (odd number of digits).
6 contains 1 digit (odd number of digits).
7896 contains 4 digits (even number of digits).
Therefore only 12 and 7896 contain an even number of digits.
```

**Constraints:**

```
1 <= nums.length <= 500
1 <= nums[i] <= 10^5
```

## Solution:

```
class Solution:
def findNumbers(nums):
return len([num for num in nums if len(str(num))%2 == 0])
num_list = [12,345,2,6,7896]
print(Solution.findNumbers(num_list))
```