# Find Winner on a Tic Tac Toe Game in Python

Tic-tac-toe is played by two players *A* and *B* on a *3* x *3* grid.

Here are the rules of Tic-Tac-Toe:

- Players take turns placing characters into empty squares (” “).
- The first player
*A*always places “X” characters, while the second player*B*always places “O” characters. - “X” and “O” characters are always placed into empty squares, never on filled ones.
- The game ends when there are 3 of the same (non-empty) character filling any row, column, or diagonal.
- The game also ends if all squares are non-empty.
- No more moves can be played if the game is over.

Given an array `moves`

where each element is another array of size 2 corresponding to the row and column of the grid where they mark their respective character in the order in which *A* and *B* play.

Return the winner of the game if it exists (*A* or *B*), in case the game ends in a draw return “Draw”, if there are still movements to play return “Pending”.

You can assume that `moves`

is **valid** (It follows the rules of Tic-Tac-Toe), the grid is initially empty and *A* will play **first**.

## Example 1:

```
Input: moves = [[0,0],[2,0],[1,1],[2,1],[2,2]]
Output: "A"
Explanation:
"A" wins, he always plays first.
"X " "X " "X " "X " "X "
" " -> " " -> " X " -> " X " -> " X "
" " "O " "O " "OO " "OOX"
```

## Example 2:

```
Input: moves = [[0,0],[1,1],[0,1],[0,2],[1,0],[2,0]]
Output: "B"
Explanation:
"B" wins.
"X " "X " "XX " "XXO" "XXO" "XXO"
" " -> " O " -> " O " -> " O " -> "XO " -> "XO "
" " " " " " " " " " "O "
```

## Example 3:

```
Input: moves = [[0,0],[1,1],[2,0],[1,0],[1,2],[2,1],[0,1],[0,2],[2,2]]
Output: "Draw"
Explanation:
The game ends in a draw since there are no moves to make.
"XXO"
"OOX"
"XOX"
```

## Example 4:

```
Input: moves = [[0,0],[1,1]]
Output: "Pending"
Explanation:
The game has not finished yet.
"X "
" O "
" "
```

**Constraints:**

```
1 <= moves.length <= 9
moves[i].length == 2
0 <= moves[i][j] <= 2
There are no repeated elements on moves. moves follow the rules of tic tac toe.
```

## Solution:

```
class Solution(object):
def tictactoe(moves):
def check(grid):
for x in range(3):
row = set([grid[x][0], grid[x][1], grid[x][2]])
if len(row) == 1 and grid[x][0] != 0:
return grid[x][0]
for x in range(3):
column = set([grid[0][x], grid[1][x], grid[2][x]])
if len(column) == 1 and grid[0][x] != 0:
return grid[0][x]
dg1 = set([grid[0][0], grid[1][1], grid[2][2]])
dg2 = set([grid[0][2], grid[1][1], grid[2][0]])
if len(dg1) == 1 or len(dg2) == 1 and grid[1][1] != 0:
return grid[1][1]
return 0
if not moves:
return ""
grid = [[0, 0, 0], [0, 0, 0], [0,0,0]]
user = 1
for x in moves:
grid[x[0]][x[1]] = user
if user == 1:
user = 2
else:
user = 1
result = check(grid)
if result == 1:
return "A"
elif result == 2:
return "B"
else:
if len(moves) == 9:
return "Draw"
else:
return "Pending"
input = [[0,0],[2,0],[1,1],[2,1],[2,2]]
print(Solution.tictactoe(input)) # A
input = [[0,0],[1,1],[0,1],[0,2],[1,0],[2,0]]
print(Solution.tictactoe(input)) # B
input = [[0,0],[1,1],[2,0],[1,0],[1,2],[2,1],[0,1],[0,2],[2,2]]
print(Solution.tictactoe(input)) # Draw
input = [[0,0],[1,1]]
print(Solution.tictactoe(input)) # Pending
```