Published at Aug 22, 2020

# Minimum Absolute Difference in Python

Given an array of distinct integers arr, find all pairs of elements with the minimum absolute difference of any two elements.

Return a list of pairs in ascending order(with respect to pairs), each pair [a, b] follows

`a, b`

are from arr`a < b`

`b - a`

equals to the minimum absolute difference of any two elements in arr

## Example 1:

```
Input: arr = [4,2,1,3]
Output: [[1,2],[2,3],[3,4]]
Explanation:
The minimum absolute difference is 1. List all pairs with difference equal to 1 in ascending order.
```

## Example 2:

```
Input: arr = [1,3,6,10,15]
Output: [[1,3]]
```

## Example 3:

```
Input: arr = [3,8,-10,23,19,-4,-14,27]
Output: [[-14,-10],[19,23],[23,27]]
```

## Constraints:

```
2 <= arr.length <= 10^5
-10^6 <= arr[i] <= 10^6
```

## Solution:

```
class Solution:
def minimumAbsDifference(arr):
if not arr:
return []
arr.sort()
min_diff = arr[1] - arr[0]
for i in range(2, len(arr)):
min_diff = min(min_diff, (arr[i] - arr[i - 1]))
result = []
for i in range(1, len(arr)):
if arr[i] - arr[i - 1] == min_diff:
result.append([arr[i - 1], arr[i]])
return result
arr = [4,2,1,3]
print(Solution.minimumAbsDifference(arr))
arr = [1,3,6,10,15]
print(Solution.minimumAbsDifference(arr))
arr = [3,8,-10,23,19,-4,-14,27]
print(Solution.minimumAbsDifference(arr))
```