Published at Aug 22, 2020

# Minimum Time Visiting All Points in Python

On a plane, there are n points with integer coordinates points[i] = [xi, yi]. Your task is to find the minimum time in seconds to visit all points.

You can move according to the next rules:

- In one second always you can either move vertically, horizontally by one unit or diagonally (it means to move one unit vertically and one unit horizontally in one second).
- You have to visit the points in the same order as they appear in the array.

## Example 1:

```
Input: points = [[1,1],[3,4],[-1,0]]
Output: 7
Explanation:
One optimal path is [1,1] -> [2,2] -> [3,3] -> [3,4] -> [2,3] -> [1,2] -> [0,1] -> [-1,0]
Time from [1,1] to [3,4] = 3 seconds
Time from [3,4] to [-1,0] = 4 seconds
Total time = 7 seconds
```

## Example 2:

```
Input: points = [[3,2],[-2,2]]
Output: 5
```

## Constraints:

```
points.length == n
1 <= n <= 100
points[i].length == 2
-1000 <= points[i][0], points[i][1] <= 1000
```

## Solution:

```
class Solution:
def minTimeToVisit(points):
if not points:
return 0
result = 0
for i in range(1, len(points)):
result += max(abs(points[i][0] - points[i - 1][0]), abs(points[i][1] - points[i - 1][1]))
return result
points = [[1,1],[3,4],[-1,0]]
print(Solution.minTimeToVisit(points)) # 7
points = [[3,2],[-2,2]]
print(Solution.minTimeToVisit(points)) # 5
```