 # Number of Burgers with No Waste of Ingredients in Python

Given two integers `tomatoSlices` and `cheeseSlices`. The ingredients of different burgers are as follows:

• Jumbo Burger: 4 tomato slices and 1 cheese slice.
• Small Burger: 2 Tomato slices and 1 cheese slice.

Return `[total_jumbo, total_small]` so that the number of remaining `tomatoSlices` equal to 0 and the number of remaining `cheeseSlices` equal to 0. If it is not possible to make the remaining `tomatoSlices` and `cheeseSlices` equal to 0 return `[]`.

## Example 1:

``````Input: tomatoSlices = 16, cheeseSlices = 7

Output: [1,6]

Explantion:
To make one jumbo burger and 6 small burgers we need 4*1 + 2*6 = 16 tomato and 1 + 6 = 7 cheese. There will be no remaining ingredients.``````

## Example 2:

``````Input: tomatoSlices = 17, cheeseSlices = 4

Output: []

Explantion:
There will be no way to use all ingredients to make small and jumbo burgers.``````

## Example 3:

``````Input: tomatoSlices = 4, cheeseSlices = 17

Output: []

Explantion:
Making 1 jumbo burger there will be 16 cheese remaining and making 2 small burgers there will be 15 cheese remaining.``````

## Example 4:

``````Input: tomatoSlices = 0, cheeseSlices = 0

Output: [0,0]``````

## Example 5:

``````Input: tomatoSlices = 2, cheeseSlices = 1

Output: [0,1]``````

## Constraints:

``````
0 <= tomatoSlices <= 10^7

0 <= cheeseSlices <= 10^7
``````

## Solution:

``````class Solution:
def numOfBurgers(tomatoSlices, cheeseSlices):
jumboBurger = tomatoSlices - 2 * cheeseSlices
if jumboBurger >= 0 and jumboBurger % 2 == 0:
x = jumboBurger/2
y = cheeseSlices - (jumboBurger / 2)
if x >= 0 and y >= 0:
return [x, y]
else:
return []
return []

print(Solution.numOfBurgers(16, 7))
print(Solution.numOfBurgers(17, 4))
print(Solution.numOfBurgers(4, 17))
print(Solution.numOfBurgers(0, 0))
print(Solution.numOfBurgers(2, 1))``````